Hi Folks,
I need a routine for creating an array of random numbers as XLs RND functions delivers 5-15 % duplicates (for my range from 1-321).
Can anyone help me?
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Array of Random Numbers (XP)
Home » Forums » AskWoody support » Productivity software by function » MS Excel and spreadsheet help » Array of Random Numbers (XP)
- This topic has 10 replies, 4 voices, and was last updated 20 years, 10 months ago.
AuthorTopicWShschwickart
AskWoody LoungerJuly 19, 2004 at 10:31 am #407515Viewing 5 reply threadsAuthorReplies-
WSHansV
AskWoody LoungerJuly 19, 2004 at 10:37 am #852998See if the replies to post 350349 and post 162299 (plus links provided in the replies) help.
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WShschwickart
AskWoody Lounger -
WShschwickart
AskWoody Lounger
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WSHansV
AskWoody LoungerJuly 19, 2004 at 10:37 am #852999See if the replies to post 350349 and post 162299 (plus links provided in the replies) help.
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H. Legare Coleman
AskWoody PlusJuly 19, 2004 at 3:07 pm #853097Your question is not completely clear. It sounds like you are trying to create an array with the integers 1 to 321 arranged in random order. If that is what you want, the code below will put the list in A1:A321 of sheet Sheet1. It can easily be modifed to put the list into an array.
Public Sub Rand321() Dim iNum(1 To 321) As Integer, iMax As Integer Dim I As Integer, J As Integer, iRand As Integer For I = 1 To 321 iNum(I) = I Next I Randomize iMax = 321 For I = 1 To 321 iRand = Int(iMax * Rnd + 1) Worksheets("Sheet1").Range("A1").Offset(I - 1, 0).Value = iNum(iRand) For J = iRand To iMax - 1 iNum(J) = iNum(J + 1) Next J iMax = iMax - 1 Next I End Sub
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H. Legare Coleman
AskWoody PlusJuly 19, 2004 at 3:07 pm #853098Your question is not completely clear. It sounds like you are trying to create an array with the integers 1 to 321 arranged in random order. If that is what you want, the code below will put the list in A1:A321 of sheet Sheet1. It can easily be modifed to put the list into an array.
Public Sub Rand321() Dim iNum(1 To 321) As Integer, iMax As Integer Dim I As Integer, J As Integer, iRand As Integer For I = 1 To 321 iNum(I) = I Next I Randomize iMax = 321 For I = 1 To 321 iRand = Int(iMax * Rnd + 1) Worksheets("Sheet1").Range("A1").Offset(I - 1, 0).Value = iNum(iRand) For J = iRand To iMax - 1 iNum(J) = iNum(J + 1) Next J iMax = iMax - 1 Next I End Sub
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WSchipshot
AskWoody LoungerJuly 19, 2004 at 7:42 pm #853284 -
H. Legare Coleman
AskWoody Plus -
H. Legare Coleman
AskWoody Plus
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WSchipshot
AskWoody LoungerJuly 19, 2004 at 7:42 pm #853285
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