I have a text box that asks what the starting number should be for a set of exhibits. I have everything working fine with plain 1,2,3 numbers. My problem is that there is also an option to number the exhibits alphabetically. If you enter the numeric value of the letter you want the series to start at, everything works fine (3 for c, 30 for dd). However, if a user wants to start the series at C, they need to be able to type C in the text box instead of 3 and have the series start at C. Is there a way to interpret the text this way? Ascii values won’t work because they don’t go a-z and then aa-zz. Any ideas???
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change alpha value to numeric (Word 2002 VBA)
Home » Forums » AskWoody support » Productivity software by function » Visual Basic for Applications » change alpha value to numeric (Word 2002 VBA)
- This topic has 7 replies, 3 voices, and was last updated 21 years, 1 month ago.
AuthorTopicWSGirlFriday
AskWoody LoungerApril 6, 2004 at 7:39 pm #403355Viewing 3 reply threadsAuthorReplies-
WSjscher2000
AskWoody LoungerApril 6, 2004 at 8:28 pm #810925How about:
Function AlphabetPosition(strLetter As String) As Integer Select Case Len(strLetter) Case 0 AlphabetPosition = 0 Case Else AlphabetPosition = InStr(1, "ABCDEFGHIJKLMNOPQRSTUVWXYZ", _ Left(strLetter, 1), vbTextCompare) End Select End Function Sub Test_AlphabetPosition() MsgBox AlphabetPosition(InputBox("Give me a letter, any letter")) End Sub
It is not case sensitive. I don’t know if this is important for your application.
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WSStuartR
AskWoody LoungerApril 7, 2004 at 3:31 am #811092I usually use the syntax
Asc(Lcase(strLetter)) – Asc(“a”) + 1
to convert a letter to a number.And if you don’t care about the readability of your code this can be simplified to
Asc(Lcase(strLetter)) – 96I have no idea which method is more efficient, but I thought you might like to see an alternate approach…
StuartR
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WSStuartR
AskWoody LoungerApril 7, 2004 at 3:31 am #811093I usually use the syntax
Asc(Lcase(strLetter)) – Asc(“a”) + 1
to convert a letter to a number.And if you don’t care about the readability of your code this can be simplified to
Asc(Lcase(strLetter)) – 96I have no idea which method is more efficient, but I thought you might like to see an alternate approach…
StuartR
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WSjscher2000
AskWoody LoungerApril 6, 2004 at 8:28 pm #810926How about:
Function AlphabetPosition(strLetter As String) As Integer Select Case Len(strLetter) Case 0 AlphabetPosition = 0 Case Else AlphabetPosition = InStr(1, "ABCDEFGHIJKLMNOPQRSTUVWXYZ", _ Left(strLetter, 1), vbTextCompare) End Select End Function Sub Test_AlphabetPosition() MsgBox AlphabetPosition(InputBox("Give me a letter, any letter")) End Sub
It is not case sensitive. I don’t know if this is important for your application.
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WSjscher2000
AskWoody LoungerApril 6, 2004 at 8:33 pm #810929Ohhhh… you permit double letters. Okay, it gets a bit more complicated:
Function AlphabetPosition(strLetter As String) As Integer Select Case Len(strLetter) Case 0 AlphabetPosition = 0 Case 1 AlphabetPosition = InStr(1, "ABCDEFGHIJKLMNOPQRSTUVWXYZ", _ strLetter, vbTextCompare) Case 2 AlphabetPosition = (InStr(1, "ABCDEFGHIJKLMNOPQRSTUVWXYZ", _ Mid(strLetter, 1, 1), vbTextCompare) * 26) + InStr(1, _ "ABCDEFGHIJKLMNOPQRSTUVWXYZ", Mid(strLetter, 2, 1), vbTextCompare) Case Else AlphabetPosition = 0 End Select End Function Sub Test_AlphabetPosition() MsgBox AlphabetPosition(InputBox("Give me a letter (or two), any letter")) End Sub
Does that do it??
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WSGirlFriday
AskWoody Lounger
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WSjscher2000
AskWoody LoungerApril 6, 2004 at 8:33 pm #810930Ohhhh… you permit double letters. Okay, it gets a bit more complicated:
Function AlphabetPosition(strLetter As String) As Integer Select Case Len(strLetter) Case 0 AlphabetPosition = 0 Case 1 AlphabetPosition = InStr(1, "ABCDEFGHIJKLMNOPQRSTUVWXYZ", _ strLetter, vbTextCompare) Case 2 AlphabetPosition = (InStr(1, "ABCDEFGHIJKLMNOPQRSTUVWXYZ", _ Mid(strLetter, 1, 1), vbTextCompare) * 26) + InStr(1, _ "ABCDEFGHIJKLMNOPQRSTUVWXYZ", Mid(strLetter, 2, 1), vbTextCompare) Case Else AlphabetPosition = 0 End Select End Function Sub Test_AlphabetPosition() MsgBox AlphabetPosition(InputBox("Give me a letter (or two), any letter")) End Sub
Does that do it??
Viewing 3 reply threads -

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