Numerous entries in one text box
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Numerous entries in one text box (97)
Home » Forums » AskWoody support » Productivity software by function » MS Access and database help » Numerous entries in one text box (97)
- This topic has 6 replies, 4 voices, and was last updated 23 years, 4 months ago.
AuthorTopicViewing 2 reply threadsAuthorReplies-
WScmotdever
AskWoody LoungerJanuary 22, 2002 at 5:55 pm #565335If instr([fieldname],”1″) > 0 then
do something here.the instr() function will return the character position that a given string falls in, therefore if the value is greater than 0, the string exists. If you know that you will be evaluating this for the numbers 1-10 then you could run a loop like this:
Dim i as integer
Dim strCriteria as stringi = 0
for i = 0 to 10
if instr(field,i) = true then
select case len(strCriteria)
case is = 0
strCriteria = i
case else
strCriteria = strCriteria & “or ” & i
end select
end ifnext i
If, in this example, the text had the numbers 1, 3, and 5 in it, then strCriteria would =
“1 or 3 or 5”This way you could build the query as
strQuery = “Select * from Table where CriteriaField = ” & strCriteriaHope this helps.
jd
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WScmotdever
AskWoody Lounger -
WSDouglas Martin
AskWoody LoungerJanuary 22, 2002 at 10:56 pm #565382At least two misteaks in your code (I’m ignoring the part at the end about setting up the query). First, instr returns an integer (the position of the second string in the first string), so you should be checking if the result is 0. Second, if [field] contains two digit numbers (e.g. 10), then your code won’t work – instr(“8,9,10″,”1”) will return non-zero (specifically, 5).
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WSClausParkhoi
AskWoody LoungerJanuary 23, 2002 at 9:31 am #565451It is not clear to me what you would like to do.
If you want to extract each comma separated value you might have a look at: http://www.mvps.org/access/strings/str0003.htm
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WScmotdever
AskWoody LoungerJanuary 24, 2002 at 10:11 pm #565932Good catch Douglas, I don’t know what planet I was on when I did that.
Arage, try this:
Public Sub ZatHere()
Dim i As Integer
Dim strCrit As StringFor i = 1 To 20
If InStr(1, “2,3,10,5”, i & “,”) > 0 Then
Select Case Len(strCrit)
Case Is > 0
strCrit = strCrit & “, or ” & i
Case Else
strCrit = i
End Select
End If
Next iMsgBox strCrit
End Sub
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WSarage
AskWoody LoungerJanuary 25, 2002 at 1:43 pm #566173thanks guys but I fixed it with a suggestion I picked up elsewhere, basically it will append proper condition to the WHERE clause of the query.
Function WHERECLAUSE() As String
Dim frmMyForm As Form
Dim strMyWhereClause, strControl1, strControl2 As String
Dim bCriteriaExists As Boolean
Dim i As IntegerbCriteriaExists = False
strMyWhereClause = “”
Set frmMyForm = Forms.Item(“frmTest”)
strControl1 = frmMyForm.Controls(“cboType”)If Len(Nz(strControl1, “”)) 0 Then
strMyWhereClause = “([NewQuery]![PromotionType] = ‘” & strControl1 & “‘) AND (”
For i = 0 To 4
strControl1 = Nz(frmMyForm.Controls(“txtEvent” & i), “”)
strControl2 = Nz(frmMyForm.Controls(“cboRegion” & i), “”)
If Not (Len(strControl1) = 0 Or Len(strControl2) = 0) Then
bCriteriaExists = True
strMyWhereClause = strMyWhereClause & ” OR ([NewQuery]![RegionalDirectorCode] = ” & strControl2 & _
” AND [NewQuery]![EventNumber] IN (” & strControl1 & “))”
End If
Next i‘Trim the extra ” OR ” before the first Region/Events criteria and put a final “)”
If bCriteriaExists = True Then
strMyWhereClause = Left$(strMyWhereClause, InStr(1, strMyWhereClause, ” OR “) – 1) & _
Right$(strMyWhereClause, Len(strMyWhereClause) – InStr(1, strMyWhereClause, ” OR “) – 3) & “)”
Else:
strMyWhereClause = “”
End IfWHERECLAUSE = strMyWhereClause
End If
End Function
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