Open Form button doesn’t link two tables (Access 2K, SR-1)

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I have a form called frmContactInfo and when I pull up a specific record, then click on “Camper” button which brings up another form called frmCmpPermInfo, it refuses to insert the ContactID from frmContactInfo into table that is attached to frmCmpPermInfo.

I had used the Toolbar Wizard to create a button that opens another form. How can I modify the event so that it would insert the contactID from the initial form into the secondary table?

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I assume that the frmCmpPermInfo is being opened to a new record and you want to set the frmCmpInfo’s ContactID to the same ID as on frmContactID. Search Help for OpenArgs and there you will find a good example of how to pass your ContactID to the new record.

hth,
Jack

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I’ve tried OpenArgs but the ContactID column in the table is still blank.

I’ve also tried: =[Forms]![frmContactInfo]![ContactID] in an unbound field attached to the frmCmpInfo with same results.

I’m using a linked table (tblContacts). Will this cause problems?

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Do you have code similar to this in the second forms On Open event?

If Not IsNull(Me.OpenArgs) Then
Me.ContactID = Me.OpenArgs
End if

Jack

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Ahhh! I have got it licked. I found a form similiar to what I needed in a book I had. From its example, here was what I did:

Create a field called contactsID, the Record Source is set to ContactsID in the table and then type this expression in Default Value field: =[Forms]![FrmContactInfo]![ContactID]

How I didn’t think of it is beyond me.

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The important things is that you have it sorted and it is working….

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